Question

In the figure below, the battery has potential difference V = 9.0 V, C2 = 3.0...

In the figure below, the battery has potential difference V = 9.0 V, C2 = 3.0 µF, C4 = 5.5 µF, and all the capacitors are initially uncharged. When switch S is closed, a total charge of 12 µC passes through point a and a total charge of 6.6 µC passes through point b.


(a) What is capacitance C1?
µF

(b) What is capacitance C3?
µF
0 1
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Answer #1
we know,Q = V*C

a) for C4, Vb = Q/c4 = 1.2v
so the P.D between s and A = 7.8v
there fore, C1 * C2/(C1 + C2) = Q/V =12/7.8 = 1.54
which gives C1 = 3.16 micro farad

b) C3 = (12-6.6)/1.2 =4.5microfarad
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Answer #2

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