8. (3pt) ROUND TO ONE DECIMAL PLACE Doctor Visit Costs An irate patient complained that the...
6. Confidence intervals A survey of 90 randomly selected families showed that 40 owned at least one television set, Find a 95% confidence interval for the proportion of all families that own at least one television set. a. b. A random sample of 20 automobiles has a pollution by-product release standard deviation of 2.3 ounces when 1 gallon of gasoline is used. Find a 90% confidence interval for the population standard deviation of the pollution by-product release. An irate patient...
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)
Suppose that the wait times for patients in an emergency room are normally distributed with an unknown mean and standard deviation. A random sample of 18 patients is taken and gives a sample mean of 25 minutes and a sample standard deviation of 2 minutes. As found above, the EBM, margin of error, for a 95% confidence interval estimate for the population mean using the Student's t-distribution is 0.99. Find a 95% confidence interval estimate for the population mean using...
idenitfy the margin of error( round to one decimal place) is it square miles? miles? miles ler hour? construct a 90% confidence interval for the population mean? interpret of 14 10 complete HW Score: 41.84, 5.86 of 14 Score: 0 of 1 pt X 6.2.18-T Question in a random sample of twee people, the mean driving dance to work was 24.1. 90% confidence interval for the population mean Interpret the results and the sandard deviation was 75 miles. Assume the...
find the critical value . round to three decimal place. find the standard deviation of the paired differences. round to one decimal place. construct 99% confidence interval. round to one decimal place. find the standard error of the sampling distrubution used in confidence interval. round to the nearest whole number. construct 90% confidence interval. round to nearest whole number A state legislator wants to determine whether his voters' performance rating (0-100) has changed from last year to this year. The...
In a random sample of six mobile devices, the mean repair cost was $80.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean mu is
per vo-Woneer 1. Fifteen randomly selected dentists were timed while brushing their own teeth for a recent study The mean amount of time spent on brushing their teeth was 2.13 minutes with a standard deviation of 0.45 minutes. Calculate the Margin of error for the mean amount of time all dentists spend brushing their teeth. Use a 99% level of confidence. Assume that the population is normally distributed. What is the confidence interval? n = 15 d.f. = 14 7=...
= Question Help For a random sample of 400 students, the mean cost for textbooks during the first semester of college was found to be $374.75, and the sample standard deviation was $30.81. Assuming that the population is normally distributed, find the margin of error of a 95% confidence interval for the population mean The margin of error for a 98% confidence interval is (Round to two decimal places as needed.) I
For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed x= 27, n=9, 0 = 6 a. Find a 95% confidence interval for the population mean The 95% confidence interval is from to (Round to two decimal places as needed.) b. Identify and interpret the margin of error. The margin of error is (Round to two decimal places as needed.) Interpret the margin of error. Choose the...
The utility bills (in dollars) of 10 randomly selected homeowners in one city are listed below. Construct a 95% confidence interval for the mean. Assume the population is normally distributed. 70, 72, 71, 70, 69, 73, 69, 68, 70, 78 (68.95, 73.05) (69.00, 78.00) (70.05, 72.95) (68.13, 73.87) Suppose a 98% confidence interval for μ turns out to be (1000, 2100). If this interval was based on a sample of size n = 22, find the value of the margin...