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= Question Help For a random sample of 400 students, the mean cost for textbooks during...
6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was...
6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was $85.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to construct a 99% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The 99% confidence interval for the population mean μ is (DD (Round to two decimal places as needed.) 6.2.21-T Question Help In a random sample...
7. A researcher surveys 40 college students to determine how much they spend on textbooks per...
7. A researcher surveys 40 college students to determine how much they spend on textbooks per semester. The responses have a sample mean of $426. The population standard deviation is known to be $83. Find the 95% confidence interval of the true mean. Assume the variable is normally distributed.
what is the margin of error and the confidence interval? Question Help In a random sample...
what is the margin of error and the confidence interval?
Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
Question Help In a random sample of live microwave ovens, the mean repair cost was $60.00...
Question Help In a random sample of live microwave ovens, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use at distribution to construct a 90% confidence interval for the population mean . What is the margin of error of ? Interpret the results The 90% confidence interval for the population mean (Round to two decimal places as needed.) is C D Enter your answer in the edit fields and...
in a random sample of four microwave ovens, the mean repair cost was 65.00 and the...
in a random sample of four microwave ovens, the mean repair
cost was 65.00 and the standard deviation was 12.50 assume the
population is normally distributed and use a t-distribution to
construct a 95% confidence interval for the population mean u what
is the margin of error of u? interpret the results
In a Round to two decimal places as needed.)
Question 9 (1 point) For a random sample of 18 recent business school graduates beginning their first job, the mean...
Question 9 (1 point) For a random sample of 18 recent business school graduates beginning their first job, the mean starting salary was found to be $43,500, and the sample standard deviation was $5,500. Assuming the population is normally distributed, find the margin of error of a 95% confidence interval for the population mean.
In a random sample of six mobile devices, the mean repair cost was $80.00 and the...
In a random sample of six mobile devices, the mean repair cost was $80.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean mu is
In a random sample of six mobile devices, the mean repair cost was $70.00 and the...
In a random sample of six mobile devices, the mean repair cost was $70.00 and the standard deviation was $11.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval forte population mean. Interpret the results. The 95% confidence interval for the population m ean μ is (DO). Round to two decimal places as needed.) The margin of error is s (Round to two decimal places as needed.)...
A simple random sample of size n equals = 18 is drawn from a population that is normally distributed. The sample mean is...
A simple random sample of size n equals = 18 is drawn from a population that is normally distributed. The sample mean is found to be x overbar equals 54 and the sample standard deviation is found to be s equals = 19 Construct a 95% confidence interval about the population mean. The 95% confidence interval is ( _____ , _____ ). (Round to two decimal places as needed.)
urgent please QUESTION 17 Thirty-six randomly selected students took a Statistics test. If the sample mean...
urgent please
QUESTION 17 Thirty-six randomly selected students took a Statistics test. If the sample mean was 72 and the sample standard deviation was 12, what will the the margin of error when constructing 95% confidence interval for the mean score of all students assuming that the population is normally distributed 4.00 5.15
6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was $85.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to construct a 99% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The 99% confidence interval for the population mean μ is (DD (Round to two decimal places as needed.) 6.2.21-T Question Help In a random sample...
7. A researcher surveys 40 college students to determine how much they spend on textbooks per semester. The responses have a sample mean of $426. The population standard deviation is known to be $83. Find the 95% confidence interval of the true mean. Assume the variable is normally distributed.
what is the margin of error and the confidence interval?
Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
Question Help In a random sample of live microwave ovens, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use at distribution to construct a 90% confidence interval for the population mean . What is the margin of error of ? Interpret the results The 90% confidence interval for the population mean (Round to two decimal places as needed.) is C D Enter your answer in the edit fields and...
in a random sample of four microwave ovens, the mean repair
cost was 65.00 and the standard deviation was 12.50 assume the
population is normally distributed and use a t-distribution to
construct a 95% confidence interval for the population mean u what
is the margin of error of u? interpret the results
In a Round to two decimal places as needed.)
Question 9 (1 point) For a random sample of 18 recent business school graduates beginning their first job, the mean starting salary was found to be $43,500, and the sample standard deviation was $5,500. Assuming the population is normally distributed, find the margin of error of a 95% confidence interval for the population mean.
In a random sample of six mobile devices, the mean repair cost was $70.00 and the standard deviation was $11.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval forte population mean. Interpret the results. The 95% confidence interval for the population m ean μ is (DO). Round to two decimal places as needed.) The margin of error is s (Round to two decimal places as needed.)...
urgent please
QUESTION 17 Thirty-six randomly selected students took a Statistics test. If the sample mean was 72 and the sample standard deviation was 12, what will the the margin of error when constructing 95% confidence interval for the mean score of all students assuming that the population is normally distributed 4.00 5.15
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