If 7.74 mL a 0.154 M solution of oxalic acid is mixed with 7.15 mL of...
If 7.74 mL a 0.154 M solution of oxalic acid is mixed with 7.15 mL of water 6.12 mL of potassium permanganate, what is the new molarity of the oxalic acid--before a reaction takes place?
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If 7.74 mL a 0.154 M solution of oxalic acid is mixed with 7.15
mL of...
If 2.34 mL a 0.219 M solution of oxalic acid is mixed with 11.11 mL of...
If 2.34 mL a 0.219 M solution of oxalic acid is mixed with 11.11 mL of water 11.88 mL of potassium permanganate, what is the new molarity of the oxalic acid--before a reaction takes place?
You titrated a 22.00 mL solution of 0.0300 M oxalic acid with freshly prepared solution of...
You titrated a 22.00 mL solution of 0.0300 M oxalic acid with
freshly prepared solution of KMnO4. If it took 48.99 mL of this
solution, what is the molarity of the KMnO4?
0.022 L of 0.300 M oxalic acid
(0.022)(0.03) = 0.00066 mol oxalic acid
0.0006 mol oxalic acid x (2 mol KMnO4)/(5 mol oxalic acid)=
0.000264 mol KMnO4
0.000264 mol/0.04899 L = 0.05388855 M KMnO4
= 0.005388 M KMnO4
where did I go wrong?
Question 7 0.1 / 1...
3. A potassium hydroxide solution was standardized against the solid acid, oxalic acid dihydrate. The volume...
3. A potassium hydroxide solution was standardized against the solid acid, oxalic acid dihydrate. The volume of the potassium hydroxide solution required to neutralize 0.317 grams of oxalic acid dihydrate was 48.82 milliliters. Calculate the molarity of potassium hydroxide solution. 4. The molarity of phosphoric acid in a popular cola is to be determined. A 355 mL sample of the cola is O 103 M potassium hydroxide solution. Calculate the molarity of phosphoric acid in the cola.
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned...
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned colorless. Further chemical analysis revealed that the evolved gas was oxygen, and the resulting solution contains potassium sulfate and manganese () sulfate; water was also formed during the same reaction. Please with 10% aq. hydrogen peroxide, answer the followings: 1) Write down the balanced chemical equation for this reaction....
You titrated a 25.00 mL solution of 0.02 M oxalic acid with a freshly prepared solution...
You titrated a 25.00 mL solution of 0.02 M oxalic acid with a freshly prepared solution of KMnO4. If it took 41.81 mL of this solution to reach the endpoint, what was the molarity of the KMnO4? 0.0119 is wrong +/- 3 sig figs.
94.20 mL of 0.800 M potassium hydroxide reacts with 125.0 mL of a solution containing oxalic...
94.20 mL of 0.800 M potassium hydroxide reacts with 125.0 mL of a solution containing oxalic acid, H2C2O4, which is a diprotic species. What is the concentration of the acid solution?
A solution of 0.154 M NaOH is used to neutralize 25.5 mL of a H2SO4 solution....
A solution of 0.154 M NaOH is used to neutralize 25.5 mL of a H2SO4 solution. If 25.0 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution? H2SO4(aq)+2NaOH(aq)→2H2O(l)+Na2SO4(aq)
A sample of oxalic acid dihydrate (126.07g/mL) with mass of 0.1473g was titrated by the addition of 35.87mL potassium hy...
A sample of oxalic acid dihydrate (126.07g/mL) with mass of 0.1473g was titrated by the addition of 35.87mL potassium hydroxide That solution of potassium hydroxide required 22.48mL to neutralize 10.00mL of nitric acid, determine molarity of the nitric acid.
Oxalic acid, H2C204, is used in the restoration of old wood. What is the molarity of...
Oxalic acid, H2C204, is used in the restoration of old wood. What is the molarity of oxalic acid if 29.78 mL of 0.538 M NaOH is required to titrate a 14.75 mL of an oxalic acid solution given the following reaction? (3 decimal places, fill in the number ONLY!) H2C2O4 (aq) + 2 NaOH (aq) → Na2C204 (aq) + 2 H20 (1)
100 mL of a 0.2 M solution of NaOH is mixed with 150 mL of a...
100 mL of a 0.2 M solution of NaOH is mixed with 150 mL of a 0.3 M HCl solution. A neutralization reaction occurs: NaOH + HCl —> NaCl + H2O. What is the molarity of the molecules in the mixed solution after the reaction has reached completion?
You titrated a 22.00 mL solution of 0.0300 M oxalic acid with
freshly prepared solution of KMnO4. If it took 48.99 mL of this
solution, what is the molarity of the KMnO4?
0.022 L of 0.300 M oxalic acid
(0.022)(0.03) = 0.00066 mol oxalic acid
0.0006 mol oxalic acid x (2 mol KMnO4)/(5 mol oxalic acid)=
0.000264 mol KMnO4
0.000264 mol/0.04899 L = 0.05388855 M KMnO4
= 0.005388 M KMnO4
where did I go wrong?
Question 7 0.1 / 1...
3. A potassium hydroxide solution was standardized against the solid acid, oxalic acid dihydrate. The volume of the potassium hydroxide solution required to neutralize 0.317 grams of oxalic acid dihydrate was 48.82 milliliters. Calculate the molarity of potassium hydroxide solution. 4. The molarity of phosphoric acid in a popular cola is to be determined. A 355 mL sample of the cola is O 103 M potassium hydroxide solution. Calculate the molarity of phosphoric acid in the cola.
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned colorless. Further chemical analysis revealed that the evolved gas was oxygen, and the resulting solution contains potassium sulfate and manganese () sulfate; water was also formed during the same reaction. Please with 10% aq. hydrogen peroxide, answer the followings: 1) Write down the balanced chemical equation for this reaction....
Oxalic acid, H2C204, is used in the restoration of old wood. What is the molarity of oxalic acid if 29.78 mL of 0.538 M NaOH is required to titrate a 14.75 mL of an oxalic acid solution given the following reaction? (3 decimal places, fill in the number ONLY!) H2C2O4 (aq) + 2 NaOH (aq) → Na2C204 (aq) + 2 H20 (1)
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