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To make a bounce pass, a player throws a 0.60 kg basketball toward the floor. The...

To make a bounce pass, a player throws a 0.60 kg basketball toward the floor. The ball hits the floor with a speed of 6.5 m/s at an angle of 82 degrees from the vertical. If the ball rebounds with the same speed and angle, what was the impulse delivered to it by the floor?
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Answer #1

The impulse I = change in momentum
                     = 2mvcosθ = 2(0.6kg) (6.5m/s) cos82
                    = 1.085 kg.m/s

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