Question

ight with a frequency of 1.69 x 1015 Hz ejects electrons from the surface of iron, which has a work function of 4.50 eV. What

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Answer #1

E- hu= 4.13 x 1015 +1.6 x 1015 → 61608 KE- E-$26-608-4.50 = 2.108 eta x=h ke P= famke da 6.626x10 34 Vaxqu1x10 3 x 2 108 x 16

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