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Question #15: Using the molecular weight (130 g/mol) of methyl (S)-2-methyl-4-oxobutanoate calculated earlier (3.8) and the m
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Answer #1

mass of reactant = 3.8g

moles of reactant = mass/molecular weight = 3.8 / 130g/mol = 0.0292 mol

mass of product = moles of methyl(S)-,methyl- 4- oxo butanoate * mol mass of product = 0.0292 * 188

theoritical yield = 5.489 g

theoritical yield = 5489 mg

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