Question

A piece of metal with a mass of 25.5 at 169.9^oC is placed in a styrofoam cup containing 35.0 g of water at 24.3^oC. Once the system has reached equilibrium, the final temperature of the water is 34.0^oC. What is the specific heat of the metal to four significant digits? The specific heat of water is 4.18 J/g-^oC.

Answer 1

Let ma mass of substance A (with Sai specific heat capacity at temperature Ta, is allowed to come in contact with the substance Bleof specific heat capacity of SB) of mass me at temperature To.. If TAY TB. Then thermal equilibrium is obtained. where higher temperature body loses heat energy and lower temperature body absorbs this energy and both of them comes to the identical temp! T). This equilibrium temp(t) las between TA4 TB (TAYTYTB) 2. Heat released by. A = Heat absorbed by B.?? MASA (TA-T) = mBiso (T-TB). .. Here, a metal of mass 25.5g at 169. ge. is placed in the styrofoam cup containing 35 g of water at 24.3°C. After equilibrium, the temperature becomes 34°C... Heat released by metal= heat absorbed by water. MA= 25.5g MB2 35g SA= ? . SB2 4.18J goe T = final tempi TA= 16 g. ge. TB = 24.300 2346 . Therefore, 25.5 gr sax( 169.9.-34) € = 35%*.4.1838 034-24:3) or, 25.5JxSA x 135.9°C = 35x4.18 x 9.7 I':. or, SA z. 35x 4.18 x 9.75. 25.59 x 135.9°C = 0.4095.Jgne! The specific heat capacity of the metal is 20:4095 uge