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Hi, may I get some help with
explanation? Thank you
Two stars of mass m =...
Two stars of mass m = 0.43 and M = 15.00 (in units of solar masses)...
Two stars of mass m = 0.43 and M = 15.00 (in units of solar masses) separated by a distance d = 8.00 (in units of AU, the earth-sun distance) revolve in circular orbits about their (common) center of mass as shown in the figure below. AL What is the orbital period of the larger star in years? Submit Answer Tries 0/6
4) A binary star system consists of two stars, one of which is 1 solar mass...
4) A binary star system consists of two stars, one of which is 1 solar mass and one of which is 2 solar masses. They are separated by a distance of 5 astronomical units and have approximately circular orbits. a) What is the orbital period of each star? b) What is the orbital velocity of each star? c) What is the angular momentum of the two star system, assuming that each star's radius is much smaller than its orbital radius?
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets...
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (Msun = 1.99 × 1030 kg) at a distance of 1.50 × 1011 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. The following problem relates to one of these planets that follows circular orbit around its star....
Plaskett's binary system consists of two stars that revolve in circular orbits around a fixed point...
Plaskett's binary system consists of two stars that revolve in circular orbits around a fixed point half-way between them. This means that the masses of the two stars are equal (see the figure below). --- M If the orbital velocity of each star is v= 188 km/s and the orbital period of each is 11.7 days, calculate the mass Mof each star. (For comparison, the mass of our Sun is 1.99x1030 kg.)
op Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass midway betwee...
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Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v | = 240 km/s and the orbital period of each is 12.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 1030 kg Your answer...
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center...
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v vector| = 170 km/s and the orbital period of each is 14.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 10^30 kg.) 1.02e-9 If you...
Need help with this problem. Thanks. Binary Stars Q1) A binary star system has a distance...
Need help with this problem. Thanks.
Binary Stars Q1) A binary star system has a distance from Earth of 42.2 light years. The distance between the stars is 1.08 x 101 m and the rotation period is 104 days. Assume equal masses of the stars, and circular orbits (centre of mass of the system is at rest relative to the Earth). a) Calculate the speed of the stars relative to the centre of mass of the system. Further assume the...
In Lecture 4, we discussed Kepler’s third law relatingthe orbital period of a planet (p) to...
In Lecture 4, we discussed Kepler’s third law relatingthe orbital period of a planet (p) to the semi-major axis (orbital distance, a) of its orbit(p2= a3). We can apply this law as long the object orbits the Sun or another object of the same mass, and the units of orbital period are in (Earth) years and the orbital distance is in Astronomical Units(AU). [1AU is equal to the distance between the Earth and the Sun]. [Note: Newton extended this law...
Hi may I get help with explanation? Thank you A 133 kg object and a 640...
Hi may I get help with
explanation? Thank you
A 133 kg object and a 640 kg are separated by 0.735 m. Find the magnitude of the net gravitational force exerted by these objects on a 42.0 kg object placed midway between them. Submit Answer Tries 0/6 At an infinitely remote distance, the net gravitational force on the third mass from the other two will be zero. Is there a point along the straight line between the two masses with...
Now M is the sum of the two masses in units of the solar mass .e. the mass of our Sun), while a i...
Now M is the sum of the two masses in units of the solar mass .e. the mass of our Sun), while a is still in AU and P in years. An important application of Newton's generalization of Kepler's third law is being able to dete mine mass of a central body based on the motion of a satellite around that body. If the satellite is much less massive than the body it's orbiting, then M is essentially equal to...
Two stars of mass m = 0.43 and M = 15.00 (in units of solar masses) separated by a distance d = 8.00 (in units of AU, the earth-sun distance) revolve in circular orbits about their (common) center of mass as shown in the figure below. AL What is the orbital period of the larger star in years? Submit Answer Tries 0/6
4) A binary star system consists of two stars, one of which is 1 solar mass and one of which is 2 solar masses. They are separated by a distance of 5 astronomical units and have approximately circular orbits. a) What is the orbital period of each star? b) What is the orbital velocity of each star? c) What is the angular momentum of the two star system, assuming that each star's radius is much smaller than its orbital radius?
Plaskett's binary system consists of two stars that revolve in circular orbits around a fixed point half-way between them. This means that the masses of the two stars are equal (see the figure below). --- M If the orbital velocity of each star is v= 188 km/s and the orbital period of each is 11.7 days, calculate the mass Mof each star. (For comparison, the mass of our Sun is 1.99x1030 kg.)
op
Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v | = 240 km/s and the orbital period of each is 12.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 1030 kg Your answer...
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v vector| = 170 km/s and the orbital period of each is 14.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 10^30 kg.) 1.02e-9 If you...
Need help with this problem. Thanks.
Binary Stars Q1) A binary star system has a distance from Earth of 42.2 light years. The distance between the stars is 1.08 x 101 m and the rotation period is 104 days. Assume equal masses of the stars, and circular orbits (centre of mass of the system is at rest relative to the Earth). a) Calculate the speed of the stars relative to the centre of mass of the system. Further assume the...
Hi may I get help with
explanation? Thank you
A 133 kg object and a 640 kg are separated by 0.735 m. Find the magnitude of the net gravitational force exerted by these objects on a 42.0 kg object placed midway between them. Submit Answer Tries 0/6 At an infinitely remote distance, the net gravitational force on the third mass from the other two will be zero. Is there a point along the straight line between the two masses with...
Now M is the sum of the two masses in units of the solar mass .e. the mass of our Sun), while a is still in AU and P in years. An important application of Newton's generalization of Kepler's third law is being able to dete mine mass of a central body based on the motion of a satellite around that body. If the satellite is much less massive than the body it's orbiting, then M is essentially equal to...
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