In each reaction box, place the best reagent and conditions from the list below.
Hint: An alkyne will be an intermediate in this multistep synthesis.
In each reaction box, place the best reagent and conditions from the list below. Hint: An...
In each reaction box, place the best reagent and conditions from the list below. Hint: An alkyne will be an intermediate in this multistep synthesis.
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. Your reagent for the first step is incorrect. This reaction involved a double elimination of HBr to form an alkyne. Which reagent is a strong base capable of carrying out this reaction ?
In each reaction box, place the best reagent and conditions from the list below. If you reduce the alkyne in step 3, you would need six steps overall to produce the final carboxylic acid. In each reaction box, place the best reagent and conditions from the list below. If you reduce the alkyne in step 3, you would need six steps overall to produce the final carboxylic acid.
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below.
In each reaction box, place the best reagent and conditions from the list below. Start with an alkyne.
In each reaction box, place the best reagent and conditions from the list below. alkyne to epoxide
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below.
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below.
In each reaction box, place the best reagent and conditions from the list below. are on the right track in forming the alkyne in ine first three steps and reducing it to the alkene in the fourth step, but H2 with Lindlar's catalyst will reduce the alkyne to the cis (or Z) alkene
In each reaction box, place the best reagent and conditions from the list below. A reagent may be used more than once.) Alkylating with ethyl bromide in steps 2 and 4 will lengthen the alkyne by two carbons at both ends but will not introduce the primary alcohol functional group.