(a) The electrical potential difference between the two points is equivalent to the amount of work done. (Since the charge is moved at constant speed, there is no energy used for changing speed, ie. No Kinetic energy change). Therefore the electrical potential energy difference is,
(b) Since the charge is moved at constant velocity, there will be no change in Kinetic Energy of the charge in the two points.
(c) The potential difference between the two points can be calculated as,
(d) Since the potential difference is negative, the final point has lesser potential as compared to the initial point where the charge was. ie. Point A has higher potential than B.
The work done by an external force to move a particle of charge -2.20 HC at...
The work done by an external force to move a particle of charge -2.20 uC at constant speed from point A to point B is 6.40x10-3J. (a) What is the difference between the electric potential energy of the charge at the two points? (b) What is the difference in the kinetic energy of the charge at the two points? (c) Determine the potential difference between the two points. (d) State which point is at the higher potential.
The work done by an external force to move a particle of charge -2.20 μC at constant speed from point A to point B is 6.40x10−310−3 J. (a) What is the difference between the electric potential energy of the charge at the two points? (b) What is the difference in the kinetic energy of the charge at the two points? (c) Determine the potential difference between the two points. (d) State which point is at the higher potential.
The work done by an external force to move a -6.60 μC charge from point A to point B is 1.80×10−3 J . If the charge was started from rest and had 4.86×10−4 J of kinetic energy when it reached point B, what must be the potential difference between A and B?
The work done by an external force to move a -7.30 μC charge from point A to point B is 1.70×10−3 J . If the charge was started from rest and had 4.80×10−4 J of kinetic energy when it reached point B, what must be the potential difference between A and B?
The work done by an external force to move a -8.20 μC charge from point a to point b is 1.10×10−3 J . If the charge was started from rest and had 4.84×10−4 J of kinetic energy when it reached point b, what must be the potential difference between a and b?
The work done by an external force to move a -6.30 μC charge from point A to point B is 1.70×10−3 J If the charge was started from rest and had 4.86×10−4 J of kinetic energy when it reached point B, what must be the potential difference between A and B?
The work done by an external force to move a -8.40 \mu C charge from point a to point b is 1.30×10-3 J. If the charge was started from rest and had 4.78×10-4 J of kinetic energy when it reached point b, what must be the potential difference between a and b?
The work done by an external force to move a -5.50 μC charge from point A to point B is 1.20×10−3 J . If the charge was started from rest and had 4.90×10−4 J of kinetic energy when it reached point B, what must be the potential difference between A and B?
ContiPeriodic Table The work done by an external force to move a-560 C charge from point a to point bis 6 80-10-4 - Part A If the charge was started from rest and had 1.80-10-J of kinetic energy when it reached pointb, what must be the potential diference between and b?
A particle that carries a net charge of -41.8 HC is held in a region of constant, uniform electric field. The electric field vector is oriented 55.2° clockwise from the vertical axis, as shown. If the magnitude of the electric field is 5.82 N/C how much work is done by the electric field as the particle is made to move a distance of d- 0.956 m straight up? 55.20 Number What is the potential difference between the particle's initial and...