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Exercises with the semi-empirical mass formula i cant get to these answers. .(5) Using the semi-empirical mass formula calculate the neutron and proton separation energies for the nucleus 51Sc, The atomic number of Ca and Sc are Z-20 and Z-21 respectively Results in Mev 4.14, 11.45 M (Ca) - (20*938.272+30*939.56) - 46952.24 M(proton) - 938.272 M(Ca) - (21*938.272+30*939.56) 47890.512 my answer is here i get zero when i use the mass 46952.24 + 938.272 - 47890.512 -0 here are the constants if you want to use binding energy Take the values of the coefficients to be ay -15.56 MeV, as 17.23 MeV, ac -0.697 MeV, am 23.285 MeV, and arA. with ap 12.0 MeV

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Answer #1

56 ドニ3- R(2.0) 15.56(so)-17.33 (So) (53-90) -12-0 ←2, 3 . 285 Or 56 し125.05

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