4, 9,7,3,5,8 a. Construct a 95% confidence interval for the population mean μ (352.848) (Round to...
Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample size of n = 5. 1, 2, 3, 4, and 30 In the given data, replace the value 30 with 5 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 95% confidence interval for the population mean, using the formula or...
Construct the confidence interval for the population mean μ. Construct the confidence interval for the population mean μ 0.98, x: 5.9, σ: 0.6, and n: 44 A 98% confidence interval for μ is OD (Round to two decimal places as needed.)
6.1.23 construct the confidence interval for the population mean μ c = 0.98, x̅ = 15.7, σ = 4.0, and n=65 A 98% confidence interval for μ is OD (Round to one decimal place as needed.)6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed.)
Assuming that the population is normally distributed, construct a 90% confidence interval for the population mean, based on the following sample size of n-6. 1, 2, 3, 4, 5, and 19 Change the number 19 to 6 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval. Find a 90% confidence interval for the population mean, using the formula or calculator. [ ] SHS (Round to two...
Construct the confidence interval for the population mean μ. 0.90, x-8.1, σ 0.8, and n-60 A 90% confidence interval for μ is (DD-Round to two decimal places as needed.)
Construct the confidence interval for the population mean μ cz 0.90, x-9.6, σ 0.4, and n 51 A 90% confidence interval for μ is (LL) (Round to two decimal places as needed.)
find z sc Construct the confidence interval for the population mean μ 0.95, x 5.2, σ 0.4, and n 58 A 95% confidence interval for μ is D (Round to two decimal places as needed)
Use the given information to find the 95% confidence interval for the population mean μ. (Round to one decimal place as needed) Weight loss on a diet: n = 35, x̅ = 4.5 kg, s = 5.2 kg
Construct the confidence interval for the population mean μ. cz 0.90, x #8.6, σ-0.8, and n 56 (Round to two decimal places as needed.)
Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample size of .n=7. 1, 2, 3, 4, 5, 6, and 15 <-----this is the data In the given data, replace the value 15 with 7 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 95% confidence interval for the population mean,...