To find the acceleration of a glider moving down a sloping air track, you measure its...
To find the acceleration of a glider moving down a sloping air track, you measure its velocity at two points (?1 and ?2); and the time t it takes between them: v1 = .21 ± 0.05 m/s v2 = .85 ± 0.05 m/s 2 = 0 t = 8.0 ± 0.1 s a. Assuming all uncertainties are independent and random, and acceleration is calculated using a = (v2-v1)/t, what should you report for a and its uncertainty? b. You calculate using an air resistance model that the acceleration should be 0.13 ± 0.01 m/s . Does your measurement agree with this prediction
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To find the acceleration of a glider moving down a sloping air
track, you measure its...
To find the acceleration of a glider moving down a sloping air track, you measure its...
To find the acceleration of a glider moving down a sloping air track, you measure its velocity at two points (?1 and ?2) and the time it takes between them: ?1 = 0.21 ± 0.05 ?/? ?2 = 0.85 ± 0.05 ?/2 ? = 8.0 ± 0.1 ? a. Assuming all uncertainties are independent and random, and acceleration is calculated using ? = ?2−?1 ? , what should you report for ? and its uncertainty? b. You calculate using...
To find the acceleration of a glider moving down a sloping air track, you measure its...
To find the acceleration of a glider moving down a sloping air track, you measure its velocities (V1 and V2) at two points and the time t it takes between them, as follows: V1=0.21+/- 0.05m/s, V2=0.85 +/- 0.05m/s, t=8.0 +/- 0.1s a) Assuming all uncertainties are independent and random, find the average acceleration, a=(v2-v1)/t , and its uncertainty. b) How well does your result in part (a) agree with your friends theoretical prediction that a=0.13 +/- 0.01m/s^2
A 1.450 kg air-track glider is attached to each end of the track by two coil...
A 1.450 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.500 N to displace the glider to a new equilibrium position, x= 0.270 m. K= 1.85 N/m The glider is now released from rest at x= 0.270 m. Find the maximum x-acceleration of the glider. 3.45×10-1 m/s^2 1. Find the x-coordinate of the glider at time t= 0.730T, where T is the period of the oscillation. 2....
A 0.450 kg air-track glider is attached to each end of the track by two coil...
A 0.450 kg air-track glider is attached to each end of the track
by two coil springs. It takes a horizontal force of 0.700 N to
displace the glider to a new equilibrium position, x= 0.270
m.
Find the effective spring constant of the system.
2.59 N/m
You are correct.
Your receipt no. is 160-5399
Previous Tries
The glider is now released from rest at x= 0.270 m. Find the
maximum x-acceleration of the glider.
1.56 m/s^2
You are correct....
1a- A 140-gram glider on a horizontal, frictionless air track is attached to a fixed ideal...
1a- A 140-gram glider on a horizontal, frictionless air track is attached to a fixed ideal spring with force constant 173 N/m. At the instant you make measurements on the glider, it is moving at 88.7 cm/s and is 3.79 cm from its equilibrium point. Use energy conservation to find: (iii) - what is the angular frequency of the oscillations, in rad/s? 1b- A 1.9-kg monkey wrench is pivoted 0.31 m from its center of mass and allowed to swing...
Prelab Assignment 5 - due at the beginning of lab 5 1. Compute the theoretical acceleration...
Prelab Assignment 5 - due at the beginning of lab 5 1. Compute the theoretical acceleration A - and its absolute uncertainty, using the following Mm measurements, and give the result in its proper form with uncertainty and unit. Uncertainty equations are given in the lab description.(4) F = 0.295 + 0.001N Force applied by the hanging mass M = 29.9 0.19 hanging mass m 190.4 0.19 glider mass 2. Compute the experimentally observed acceleration and its absolute uncertainty using...
Data Sheet B. Constant Acceleration Measured distance from single leg to double leg of air track...
Data Sheet B. Constant Acceleration Measured distance from single leg to double leg of air track L Height of riser block d Spark timer setting 10 Number of time intervals between circled dots Time Δ1 between circled dots ' Angle of nlineplanen Aaron Spark timer Δ4" settingAngle of sparks/s - Circled Dot Elapsed Total Displacements) Between Average Velocity Number Displacement Ar (m) | Even-Numbered | . . ArtM(ms) t (s) x (m) 0 0.4 0.1 0 0 0 O. 1...
Find the x-coordinate of the glider at time t= 0.570T, where T is the period of...
Find the x-coordinate of the glider at time t= 0.570T, where T
is the period of the oscillation.
A 0.750 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.500 N to displace the glider to a new equilibrium position, x= 0.270 m. 000000000 Find the effective spring constant of the system. 1.85 N/m You are correct. Your receipt no. is 149-3397 Previous Tries The glider is now...
I need help for numbers 1 and 3. For number one I measured the height of...
I need help for numbers 1 and 3. For number one I
measured the height of the track at angle. One of the heights was
.082m. hypotenuse 1.013m. I did sin^-1(.082/1.013) and got 4.64
degrees. I used a sensor and aquired data for change in v and t as
a glider fell down the track. I calculated the acceleration at that
height and angle as -10.18 m/s^2. final V was 1.48, initial V .687.
final t=.0675, initial t= .1454.
For...
You measure the length of a board with a ruler that is older and has a...
You measure the length of a board with a ruler that is older and has a worn-down end. If you align the end of the board with the end of the ruler, what type of uncertainty does the end of the ruler contribute to the measurement? A) Random B) Systematic The average height of children in kindergarten in Winnipeg is found by measuring the height of one randomly-selected child in every kindergarten class in the city. What type of uncertainty...
A 0.450 kg air-track glider is attached to each end of the track
by two coil springs. It takes a horizontal force of 0.700 N to
displace the glider to a new equilibrium position, x= 0.270
m.
Find the effective spring constant of the system.
2.59 N/m
You are correct.
Your receipt no. is 160-5399
Previous Tries
The glider is now released from rest at x= 0.270 m. Find the
maximum x-acceleration of the glider.
1.56 m/s^2
You are correct....
Prelab Assignment 5 - due at the beginning of lab 5 1. Compute the theoretical acceleration A - and its absolute uncertainty, using the following Mm measurements, and give the result in its proper form with uncertainty and unit. Uncertainty equations are given in the lab description.(4) F = 0.295 + 0.001N Force applied by the hanging mass M = 29.9 0.19 hanging mass m 190.4 0.19 glider mass 2. Compute the experimentally observed acceleration and its absolute uncertainty using...
Data Sheet B. Constant Acceleration Measured distance from single leg to double leg of air track L Height of riser block d Spark timer setting 10 Number of time intervals between circled dots Time Δ1 between circled dots ' Angle of nlineplanen Aaron Spark timer Δ4" settingAngle of sparks/s - Circled Dot Elapsed Total Displacements) Between Average Velocity Number Displacement Ar (m) | Even-Numbered | . . ArtM(ms) t (s) x (m) 0 0.4 0.1 0 0 0 O. 1...
Find the x-coordinate of the glider at time t= 0.570T, where T
is the period of the oscillation.
A 0.750 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.500 N to displace the glider to a new equilibrium position, x= 0.270 m. 000000000 Find the effective spring constant of the system. 1.85 N/m You are correct. Your receipt no. is 149-3397 Previous Tries The glider is now...
I need help for numbers 1 and 3. For number one I
measured the height of the track at angle. One of the heights was
.082m. hypotenuse 1.013m. I did sin^-1(.082/1.013) and got 4.64
degrees. I used a sensor and aquired data for change in v and t as
a glider fell down the track. I calculated the acceleration at that
height and angle as -10.18 m/s^2. final V was 1.48, initial V .687.
final t=.0675, initial t= .1454.
For...
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