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To find the acceleration of a glider moving down a sloping air track, you measure its...

To find the acceleration of a glider moving down a sloping air track, you measure its velocities (V1 and V2) at two points and the time t it takes between them, as follows:


V1=0.21+/- 0.05m/s, V2=0.85 +/- 0.05m/s, t=8.0 +/- 0.1s


a) Assuming all uncertainties are independent and random, find the average acceleration, a=(v2-v1)/t , and its uncertainty.


b) How well does your result in part (a) agree with your friends theoretical prediction that a=0.13 +/- 0.01m/s^2

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Answer #1


The acceleration is the rate of change in velocity -У,-1-0.85-0.21 0.08 m/s Hence, average acceleration is 0.08 m/s. The uncertainty in the velocity is, Αν Δν 0.05 +0.05 v V-Vi 0.85-0.21 The uncertainty in the time is, Av 0.10 -0.1563 0.0125 The uncertainty in the acceleration is, 0.1563+0.0125 0.1688 al Ал-:0.1688x 0.08_+0.0 135 The uncertainty in the acceleration is 0.08 m/s2 +0.0135 m/s The acceleration is, 0.13 m/s +0.01 m/s Hence, our agreement in the part (a) does not agree with this prediction.

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