PRICE | SHARES | |||||||||||
Company | A | B | C | A | B | C | ||||||
Day 1 | $13 | $25 | $51 | 540 | 360 | 210 | ||||||
Day 2 | 11 | 22 | 57 | 540 | 360 | 210 | ||||||
Day 3 | 13 | 50 | 54 | 540 | 180a | 210 | ||||||
Day 4 | 12 | 50 | 25 | 540 | 180 | 420b | ||||||
Day 5 | 11 | 50 | 27 | 540 | 180 | 420 | ||||||
aSplit at close of day 2. bSplit at close of day 3. |
Calculate a Dow Jones Industrial Average for days 1 through 5. Do not round intermediate calculations. Round your answers to three decimal places.
Day 1:
Day 2:
Day 3:
Day 4:
Day 5:
Problem 4-05 PRICE SHARES C B $50 Company A B Day 1 $13 $22 Day 2 1124 Day 3 B 14 44 Day 4 1145 Day 5 B 12 42 aSplit at close of day 2. bSplit at close of day 3. A 470 470 470 470 470 400 400 2002 200 200 270 270 270 5400 27 540 Calculate a Standard& Poor's Index for days 1 through 5 using a beginning index value of 10. Do not round intermediate...
Problem 4-04 C PRICE SHARES Company ABC AB Day 1 $14 $20 510 350 Day 2 10 21 59510 350 Day 3 - 15 40 52 510 175a Day 4 1 13 41 510 175 Day 5 1041 26 510 175 aSplit at close of day 2. bSplit at close of day 3. 280 280 280 5606 560 Calculate a Dow Jones Industrial Average for days 1 through 5. Do not round intermediate calculations. Round your answers to three decimal...
PRICE SHARES Company A B C A B C Day 1 $13 $24 $53 550 380 200 Day 2 10 25 60 550 380 200 Day 3 15 48 58 550 190a 200 Day 4 10 48 28 550 190 400b Day 5 11 50 29 550 190 400 aSplit at close of day 2. bSplit at close of day 3. Calculate a Standard& Poor's Index for days 1 through 5 using a beginning index value of 10. Do not...
Candidate
MARK
COMP
CERTIF
1
476
111
68
2
457
92
46
3
540
90
50
4
551
107
59
5
575
98
50
6
698
150
66
7
545
118
54
8
574
110
51
9
645
117
59
10
556
94
97
11
634
130
57
12
637
118
51
13
390
91
44
14
562
118
61
15
560
109
66
II. Consider the following data for 15 subjects with two predictors. The dependent variable, MARK, is...
Can somone show me how to do the 1st problem? Need to
find the LS and SS for the fit and the LH and SH for the hole.
Fits are all SHAFT BASIS METRIC but the shaft and hole diameters can not be used right out of the table. This is because the 3mm shaft tolerance does not match. You will need to lookup the "Fit" from the table, and then use the LS (Largest Shaft) and SS (Smallest Shaft)...
Nash Company's record of transactions for the month of April was as follows. Purchases Sales 360 S6.00 April 3 300@ $10.00 9 840 10.00 11 360 11.00 23 720 11.00 April 1 (balance on hand 900 6.08 4 8 480e 6.40 720 650 420 6.60 13 27 540@ 12.00 21 300 6.79 2.760 29 3.180 Assuming that periodic inventory records are kept in units only, calculate the average-cost per unit. (Round answer to 2 decimal places, es. 2.76 Average-cost per...
Bag Blue Orange Green Yellow Red Brown Total Number of Candies 1 9 13 14 10 7 7 60 2 13 10 6 9 9 8 55 3 13 12 4 10 9 6 54 4 16 13 8 6 6 8 57 5 10 10 12 5 15 4 56 6 9 18 3 6 12 12 60 7 11 13 6 15 8 6 59 8 12 18 5 9 6 5 55 9 12 10 8 15...
Quiz: QuizO2 Time Remaining: 00:35:45 Submit Qubz This Question: 9 pts 5 of 16 (13 complete) This Quiz: 31 pts possible West Battery Corp. hasrecently been receiving complaints from retailers that its 9-volt batteries are not lasting as long as other name brands. James West, head of the TQM program at West's Austin plant, believes there is no problem because his batteries have had an average life o 55 hours about 10% onger than competitors' models. To raise he lifetime...
Using Excel to calculate the following: 1. The future value of $3 invested every day, 360 days per year, for 50 years at 8% interest. Hint: Interest is compounding daily. 2. The future value of $1,080 ($3 x 360) invested annually for 50 years at 8% interest. 3. The payment for a mortgage with a principal amount of $150,000, an interest rate of 5%, fully amortized over 30 years. 4. The price today of 15 year bond that has a...
West Battery Corp. has recently been receiving complaints from retailers that its 9-volt batteries are not lasting as long as other name brands. James West, head of the TQM program at West's Austin plant, believes there is no problem because his batteries have had an average life of 5050 hours, about 10% longer than competitors' models. To raise the lifetime above this level would require a new level of technology not available to West. Nevertheless, he is concerned enough...