let us first determine the horizontal and vertical forces
so from the diagram we have
Fx=4/5*80=64lb and Fy=50*cos30=43.3lb
now taking the sum of the moments
M=64*4
-43.3*3=126.1ft.lb
now taking the sum of the moment about A
Ma=-64*3+64*7+43.3*2-43.3*5=126.1ft.lb
now taking the sum of the moment about B
Mb=43.3*2-43.3*5-64*1+64*5=126.1ft.lb
so the resultant couple=126.1ft.lb+126.1ftlb=252.2ft.lb
so the answer is 252 ft.lb
Find the resultant couple GROUP PROBLEM SOLVING I 2-3ft Given: Two couples act on the beam...
Two couples act on the cantilevered beam as shown. Find the magnitude of F so that the resultant couple moment is 500 lb-ft.
part D please.
Two couples act on the frame. d = 4 ft. (Figure 1) Figure < 1 of 1 > 2 ft + 3ft- 450 lb BIZ 1 ft 30° 50 lb 80 lb 80 lb We were unable to transcribe this imagePart C Select the correct expression for the sum of the moments of all the force components about point B. • Mc=- | (80)(1) + (80)(5) + 50 cos(30°)(2) – 50 cos(30°)(5) Mc =- (80 1) +...
Four forces act on a frame as shown below. Determine the resultant force and the resultant moment of the four forces acting on the frame about point A. Write the result in Cartesian form. Use 55lb, 75lb. 30. Sft, 6ft. t and 3ft instead of 40 lb, 60 ib, 30, 3 ft, 4 ft, 2 ft and 1 ft. Also, use 9. 12, and 15 triangle instead of 3, 4, and 5 triangle. 1-4t lb 40 1b B Ift 30...
To calculate the resultant couple and force at a point for a
given force and couple system.
Two forces F1F1F1 = 75 NN and F2F2F2 = 255 NN and two moments
M1M1M1 = 100 N⋅mN⋅m and M2M2M2 = 50 N⋅mN⋅m act on the beam as shown
in (Figure 1).
DO NOT ATTEMPT TO ANSWER IF YOU ARE NOT AN EXPERT, AVOID
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I
want clear answer and (do Step 1 and Step 2)
Replace the forces acting on the beam by an equivalent resultant force and couple moment acting at point A. 200 lb 50 lb _3ft 3 ft 3ft30 3100lb Given: A 2-D force system with geometry Find: FRA: MRA Solution: Step : Sum all the x and y components of the forces to find FRA. Step 2: Find and sum all the moments resulting from moving each force component to...
2. There are two forces acting at C. What is the resultant from the two forces? What is the moment about the point o generated from the resultant force? Find the component of the moment about point which goes in the direction of OA. (20 pts.) 1 ft 3 ft F = (-20i + 10j + 30k) lb B 2 ft F. =-101 - 30j + 50k) lb
2. There are two forces acting at C. What is the resultant from the two forces? What is the moment about the point o generated from the resultant force? Find the component of the moment about point O which goes in the direction of OA. (20 pts.) 1 ft ft 3 ft F = {-20i + 10j + 30k) lb B 2 ft F = (-10i - 30j + 50k) ID
Solve the question
GROUP PROBLEM SOLVING II Given: F (80 k N and F= {-80k} N Find: The couple moment acting on the pipe assembly using Cartesian vector 300 mm notation. Plan: 1) Use M-rx F to find the couple moment 2) Set rs and F 180 k N. 3) Calculate the cross product to find M 0
Answers shown below please show the
process/explain
Problem 9: Consider the statically indeterminate beam shown below with the given loading. E and I are constant. a) Find the rotation at node 2 using the stiffness method. b) Find the unknown reactions using equilibrium and the force-displacement relationships. c) Draw final free body diagrams of the two beam elements and node 2, showing all forces with the correct values and directions. 2.0 k/ft Problem 9: 450 a) θ2_El b) M1 180k...
3. Two forces and a moment act on the bracket below. a) Find the resultant force. b) Replace the given system with an equivalent force-couple system acting at B. Sketch the result in the space provided below. Replace the given system with an equivalent system consisting of only a force whose line of action intersects the x axis. Determine the coordinate, d, of the point of intersection on the x axis. Sketch the result in the space provided below.4 SOON...