Question

A bead with a mass of 0.050 g and a charge of 15 nC is free...

A bead with a mass of 0.050 g and a charge of 15 nC is free to slide on a vertical rod. At the base of the rod is a fixed 10 nC charge. In equilibrium, at what height above the fixed charge does the bead rest?

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Answer #1

Prepare:

The repulsive force between the charged particles is equal to the weight of the charged bead that is held in equilibrium.

The distance between the two charges is the height at which the second charge is from the ground.

Solve:

Given

Mass of the bead, charge of the bead, Charge on the ground is, on substituting the values

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