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-5 points SesPSET9 23 P052 A proton is projected in the positive x direction into a...
A proton is projected in the positive x direction into a region of uniform electric field...
A proton is projected in the positive x direction into a region of uniform electric field E = (-6.90 × 105) Î N/C at t = 0, The proton travels 6.90 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude direction | Select- m/s2 (b) Determine the initial speed of the proton. magnitude direction | Select- m/s (c) Determine the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into a region of uniform electric field...
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.70 ✕
105) î N/C at t = 0. The
proton travels 7.50 cm as it comes to rest.
(a) Determine the acceleration of the proton.
magnitude
m/s2
(b) Determine the initial speed of the proton.
magnitude
m/s
(c) Determine the time interval over which the proton comes to
rest.
s
A proton is projected in the positive x direction into a region of uniform electric field...
A proton is projected in the positive x direction into a region of uniform electric field E (-5.20 x 10) i N/C at t 0. The proton travels 6.00 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude directionSelect m/s (b) Determine the initial speed of the proton. magnitude direction-Select m/s (c) Determine the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into a region of uniform electric field = (-5.60 105) N/C at t = 0...
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.60 105)
N/C at t = 0. The proton travels 6.30 cm as it comes to rest.
(a) Determine the acceleration of the
proton.
(b) Determine the initial speed of the proton.
(c) Determine the time interval over which the proton comes to
rest.
s
magnitude
m/s2
direction
---Select--- +x −x +y −y +z −z
magnitude
m/s
direction
---Select--- +x −x +y −y...
proton is projected in the positive x direction into a region of uniform electric field E...
proton is projected in the positive x direction into a region of uniform electric field E with arrow = (-5.90 ✕ 105) î N/C at t = 0. The proton travels 6.00 cm as it comes to rest. (1)Determine the acceleration of the proton.&direction (2) Determine initial speed of proton &direction (3)Determine the time interval over which the proton comes to rest.
3) 52. A proton is projected in the positive x direction into a region of a...
3) 52. A proton is projected in the positive x direction into a region of a uniform electric field È .. 6' 10' N/c:7 at t = 0. The proton travels 7.00 cm as it comes to rest. Determine (a) the acceleration of the proton, (b) its initial speed, and (c) the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into aregion of uniform electric field E = -6.60 105i N/C att = 0....
A proton is projected in the positive x direction into
aregion of uniform electric field E = -6.60
105i N/C att = 0. The proton
travels 7.40 cm as it comes to rest.(a)
Formula for calculating the value of the acceleration (a) of
theproton is
a
= Eq / m
=
-(-6.60
105i N/C)(1.6*10-19C)
/(1.67*10-27kg)
=
-6.32*1013m/s2i
So magnitude of the acceleration of the particle is a
=6.32*1013m/s2And its direction is
alongnegative x direction
(b)
Distance (S) traveled =7.40cm =...
A proton travels with a speed of 5.00 x 106 m/s at an angle of 61°...
A proton travels with a speed of 5.00 x 106 m/s at an angle of 61° with the direction of a magnetic field of magnitude 0.150 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? (b) What is the proton's acceleration? (Give the magnitude.) Need Help? Read
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x...
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 107 m/s and experiences an acceleration of 1.50 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. 1.11e-2 magnitude Apply the expression for the force on a charge moving through a magnetic field to find the field from the acceleration it produces. T direction - Need Help? Read It Master...
A proton moves at 4.50 x 105 m/s in the horizontal direction
A proton moves at 4.50 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60 x 103 N/C. Ignoring any gravitational effects, find (a) the time interval required for the proton to travel 5.00 cm horizontally, (b) its vertical displacement during the time interval in which it travels 5.00 cm horizontally, and (c) the horizontal and vertical components of its velocity after it has traveled 5.00 cm horizontally.25a) Find the (x,y)...
A proton is projected in the positive x direction into a region of uniform electric field E = (-6.90 × 105) Î N/C at t = 0, The proton travels 6.90 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude direction | Select- m/s2 (b) Determine the initial speed of the proton. magnitude direction | Select- m/s (c) Determine the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.70 ✕
105) î N/C at t = 0. The
proton travels 7.50 cm as it comes to rest.
(a) Determine the acceleration of the proton.
magnitude
m/s2
(b) Determine the initial speed of the proton.
magnitude
m/s
(c) Determine the time interval over which the proton comes to
rest.
s
A proton is projected in the positive x direction into a region of uniform electric field E (-5.20 x 10) i N/C at t 0. The proton travels 6.00 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude directionSelect m/s (b) Determine the initial speed of the proton. magnitude direction-Select m/s (c) Determine the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.60 105)
N/C at t = 0. The proton travels 6.30 cm as it comes to rest.
(a) Determine the acceleration of the
proton.
(b) Determine the initial speed of the proton.
(c) Determine the time interval over which the proton comes to
rest.
s
magnitude
m/s2
direction
---Select--- +x −x +y −y +z −z
magnitude
m/s
direction
---Select--- +x −x +y −y...
3) 52. A proton is projected in the positive x direction into a region of a uniform electric field È .. 6' 10' N/c:7 at t = 0. The proton travels 7.00 cm as it comes to rest. Determine (a) the acceleration of the proton, (b) its initial speed, and (c) the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into
aregion of uniform electric field E = -6.60
105i N/C att = 0. The proton
travels 7.40 cm as it comes to rest.(a)
Formula for calculating the value of the acceleration (a) of
theproton is
a
= Eq / m
=
-(-6.60
105i N/C)(1.6*10-19C)
/(1.67*10-27kg)
=
-6.32*1013m/s2i
So magnitude of the acceleration of the particle is a
=6.32*1013m/s2And its direction is
alongnegative x direction
(b)
Distance (S) traveled =7.40cm =...
A proton travels with a speed of 5.00 x 106 m/s at an angle of 61° with the direction of a magnetic field of magnitude 0.150 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? (b) What is the proton's acceleration? (Give the magnitude.) Need Help? Read
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 107 m/s and experiences an acceleration of 1.50 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. 1.11e-2 magnitude Apply the expression for the force on a charge moving through a magnetic field to find the field from the acceleration it produces. T direction - Need Help? Read It Master...
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