Question

Which compound(s) will not form a yellow precipitate when treated with excess iodine in the presence of NaOH? A B C D

Answer 1

Concepts and reason

The concept used to solve this question is halogenation at the alpha carbon in base.

If the given compound reacts with excess ${\rm{B}}{{\rm{r}}_2}$ in the presence of base forms a carboxylate ion and a haloform.

Fundamentals

${\rm{CH}}{{\rm{X}}_3}$ is commonly known as haloform.

Halogenation of methyl ketone with excess halogen, known as haloform reaction.

The strcuture is as follows:

The strcuture is as follows:

The structure is as follows:

The structure is as follows:

Ans:

The compounds that do not form yellow precipitate are as follows: