IF YOU CANT ANSWER EACH PART THEN DONT ANWSER IT AT ALL please check your work....
МУ Note 6.3 points Use the flow charts for line integrals and surface integrals to help you decide the best way to find the answer to the following problem. Let S be the surface that is the boundary of the baxy2+z s 9 and let A be a twice continuously differentiable vector field. It is known that the flux of the vector field F V x A through the upper hemispherev9-x-y2 with upward orientation is equal to 3. Determine the...
please just the final answer for both
Evaluate the surface Integral || 5. ds for the given vector fleld F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = yi - xj + Szk, S is the hemisphere x2 + y2 + y2 = 4, 220, oriented downward 26.677 X Evaluate the surface integral llo F.ds for the given vector field F...
PLEASE SHOW ALL WORK
NEATLY! THANK YOU!
(10 pts) Let F(x, y, z) = (x + y, y - 1, e), and let S be the part of the surface z = 9. 22 - y2 above the plane z=5, with downward orientation. Evaluate the flux of F across S by computing the surface integral IsF. ds.
Evaluate the surface integral ∫∫S F·ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = xyl + yzj + zxk S is the part of the paraboloid z = 2 = x2 - y2 that lies above the square 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, and has upward orientation_______
Show all work and use correct notation for full credit. Stokes' Theorem: Let S be an orientable, piecewise smooth surface, bounded by a simple closed piecewise smooth curve C with positive orientation. Let F be a vector field with component functions that have continuous partial derivatives on an open region in R3 that contains S. Then | | curl(F) . ds F-dr = where curl(F) = ▽ × F. (2 Credits) Let S be the cone given by {(z, y,...
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = xzey i − xzey j + z k S is the part of the plane x + y + z = 7 in the first octant and has upward orientation.
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = x i − z j + y k S is the part of the sphere x2 + y2 + z2 = 36 in the first octant, with orientation toward the origin
I asked this question earlier but the answer I received was not
correct. I am especially having a problem with part (a). Please
help!
7. Let S be the part of the sphere 2 y2 + z2 = 4 between the planes z 1, oriented with outward pointing normal. Let z = -1 and R3IR be the vector field -4y2, 24 - 2) f(x,y) = (yz+ 2x, -xz + (a) Draw a careful sketch of S. ldentify the boundary aS...
I'll ask again, Please DON'T use the divergence
theroem, I cant do the surface integral.
(7) Let V be the region in R3 enclosed by the surfaces ++22,0 and1. Let S denote the closed surface of V and let n denote the outward unit normal. Calculate the flux of the vector field Fx, y, z)(2 - 2)j 22k out of V and verify Gauss' Divergence Theorem holds for this case. That is, calculate the flux directly as a surface integral...
Evaluate the surface integral | Fids for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the JS positive (outward) orientation. F(x, y, z) = y i + (z - y)j + xk S is the surface of the tetrahedron with vertices (0, 0, 0), (4, 0, 0), (0, 4, 0), and (0, 0, 4)