Question

For each of the following alcohols, which method of synthesis, (a) hydroboration?oxidation or (b) oxymercuration?reduction, can produce the alcohol relatively free of constitutional isomers and diastereomers? (Drag an alcohol to the appropriate bin if it can be made by that method.)r each of the following alcohols, which method of synthesis, (a) hydroboration- oxidation or (b) oxymercuration-reduction, can produce the alcohol relatively free of constitutional isomers and diastereomers? (Drag an alcohol to the appropriate bin ifit can be made by that method.) (a) hydroboration-oxidation (b) oxymercuration-reductiorn ..OH OH OH CH3CH2 CH CH2CH2CH3 OH OH OH CH3CH2 CH3CH2 CH CH2CH2CH3 OH OH

0 0
Add a comment Improve this question Transcribed image text
Answer #1
Concepts and reason

Retrosynthesis: It’s a method of identifying the starting materials from the given target compound. In this method the target molecule was disintegrated into its respective most possible precursor.

Alkene: Its class of organic compound with functional group of carbon-carbon (C=C)\left( {{\rm{C}} = {\rm{C}}} \right) double bond. Alkenes are reactive due to the presence of π{\bf{\pi }} -bonds. Alkenes undergo addition reactions, oxidations and polymerization, and so forth.

Hydration reaction: It’s a type of addition reaction, in which water molecule is added along the double bond of the alkene to produce saturated alcoholic derivatives. In case of unsymmetrical alkene the addition reaction may result in two type of product they are explained as Markonikov product and anti Markonikov product.

Markonikov product: During the hydration of alkene the hydroxyl group was attached to the more substituted alkenic carbon and hydrogen forms bond with less substituted alkenic carbon.

Anti-Markonikov product: Its reverse of Markonikov product, in which the hydroxyl group attach to the less substituted alkenic carbon and the hydrogen was attached to the more substituted carbon alkenic carbon.

Hydroboration-oxidation: Addition of water molecule towards the alkene was done with aid of BH3{\rm{B}}{{\rm{H}}_{\rm{3}}} and H2O2{{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}} , which resulted in the formation of anti-Markonikov product

in major amount. Moreover, stereo chemically it’s a “syn-type” addition, that is OH{\rm{OH}} and H{\rm{H}} were added from the same side.

Oxymercuration-reduction: In this reaction water molecule was added to alkene with the help of mercuric acetate and sodium borohydride. oxymercuration leads to the formation of Markonikov product as predominant. Stereo chemically this is “anti-type” addition reaction, in which the OH{\rm{OH}} and H{\rm{H}} were added from the opposite side.

Fundamentals

Mechanism for hydroboration of alkene:

Rз
R1
R3
R1
R3
R1
R2-с-
R2с-c-н
Rз
R1
Rz-с-
R1
Rз
Rz~с-c-н
ВНз
н-
—ВН2
н
Вн2
ВН2
н
Н
R2
НОО
Но
Rз
H
R1
R2-с
ОН
н

Mechanism for oxymercuration of alkene:

н
н.
OH R3
ОН Rз
R2 C-CH
R1
NaBH4
R3
R2 C-CH
R1
Hg(OAc)2R2C-CH
R3
R1
H
R1
Hg
Hg
н
R2
OAc
OAc

Given alcohols

Он
Н2 Т Н2 Н2
Hас—с-с-с-с-сн,
н
н
н
он
Он
н
н
Он

Using retro synthetic approach the alkenes precursors were identified as shown below.

H
-H
ОН
H
он
ОН
hydration
1-methylcyclopentene

All three cyclopentane alcohol derivatives can be obtained by the hydration of methyl-cyclopentene.

Н2
Нydration H,с —с -ҫ-с-с -сHз
нн
Н2
ОН
Н2 Н2 Н2
Нас—с -с-с -с -CHз
н
hex-3-ene

Hydroboration-oxidation of the identified alkene precursors are given below

н
ВНз, NaOH
На02
H
Он
1-methylcyclopentene
Он
Н2 I Н2 Н2
Нас —с -с—С -с -СНз
Н
Нас—с -с-С-С-сн. ВНз, NaOH.
H202
Н2
Н2
нн
hex-

Oxymercuration-reduction for the first alkene gives the following products.

Он
Hg/OAc), Н20
NaBH
н
1-methylcyclopentene
Он
Н2 I Н2 Н2
Нас —с -с-С -С -сH3
н
Hg(OAc)2, H20
На
Н2
-С-С -С -СН,
нн
Нас—с
NaB

The alcohol given below cannot be prepared by either hydroboration-oxidation or oxymercuration method.

H
OH

Since hex-3-ene is symmetric, hydroboration and oxymercuration of it will lead to the same alcohol derivative.

Ans:

The alcohol obtained by the hydroboration-oxidation and oxymercuration-reduction were presented in their respective bins

Oxymercuration-reduction
Hydroboration-oxidation
|. ОН
ии
н
н
ОН
ОН
ОН
Н2
-C-
H
Н2
Н2
Н2
-C
H
Н2
C
Н2
-с — сНз
C
Нас—
С
C
Нас

Add a comment
Know the answer?
Add Answer to:
For each of the following alcohols, which method of synthesis, (a) hydroboration?oxidation or (b) oxymercuration?reduction, can...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • For each of the following alcohols, which method of synthesis, (a) hydroboration-oxidation or (b) oxymercuration-reduction, can...

    For each of the following alcohols, which method of synthesis, (a) hydroboration-oxidation or (b) oxymercuration-reduction, can produce the alcohol relatively free of constitutional isomers and diastereomers? (Drag an alcohol to the appropriate bin if it can be made by that method.) hydroboration-oxidation oxymercuration-reduction One of the alcohols can be formed by either method of synthesis, starting from a symmetrical alkene.

  • For each of the following alcohols, which method of synthesis, (a) hydroboration?oxidation or (b) oxymercuration?reduction, can...

    For each of the following alcohols, which method of synthesis, (a) hydroboration?oxidation or (b) oxymercuration?reduction, can produce the alcohol relatively free of constitutional isomers and diastereomers? (Drag an alcohol to the appropriate bin if it can be made by that method.)

  • The four constitutionally isomeric alcohols shown below can each be made selectively by one or both...

    The four constitutionally isomeric alcohols shown below can each be made selectively by one or both of hydroboration/oxidation or oxymercuration/demercuration of one or two constitutionally isomeric alkenes. For each of (a)-(d) write one or two alkenes (as indicated) that is/are appropriate starting materials, and for each alkene which of two reagent combinations is needed to produce the indicated alcohol. You can disregard stereochemistry in this problem, and focus just on regiochemistry. In other words, be sure the OH will become...

  • Alkene reaction and mechanisms practice exercise 1) O₃ 2) (CH3)2S 25) Treatment of cyclopentene with peroxybenzoic...

    Alkene reaction and mechanisms practice exercise 1) O₃ 2) (CH3)2S 25) Treatment of cyclopentene with peroxybenzoic acid A) results in oxidative cleavage of the ring to produce an acyclic compound B) yields a meso epoxide C) yields an equimolar mixture of enantiomeric epoxides D) gives the same product as treatment of cyclopentene with Os04 E) none of the above 26) Provide a detailed, step-by-step mechanism for the reaction shown below. но Br2 na + HBT Br 27) Provide a detailed,...

  • 13 SN1: Synthesis of tert-Butyl Chloride Alkyl halides can be prepared from their corresponding alcohols via...

    13 SN1: Synthesis of tert-Butyl Chloride Alkyl halides can be prepared from their corresponding alcohols via an acid catalyzed substitution reaction. The mechanism of these acid catalyzed substitution reactions are labeled as Syl (substitution, nucleophilic, unimolecular) and S2 (substitution, nucleophilic, bimolecular). Tertiary alcohols follow the Snl route, primary alcohols follow the S2 route, and secondary alcohols can follow either path. Under acidic conditions, the mechanism (Figure 1) of the Sul reaction involves rapid protonation of the alcohol, followed by the...

  • 13 SN1: Synthesis of tert-Butyl Chloride Alkyl halides can be prepared from their corresponding alcohols via...

    13 SN1: Synthesis of tert-Butyl Chloride Alkyl halides can be prepared from their corresponding alcohols via an acid catalyzed substitution reaction. The mechanism of these acid catalyzed substitution reactions are labeled as Syl (substitution, nucleophilic, unimolecular) and S2 (substitution, nucleophilic, bimolecular). Tertiary alcohols follow the Snl route, primary alcohols follow the S2 route, and secondary alcohols can follow either path. Under acidic conditions, the mechanism (Figure 1) of the Sul reaction involves rapid protonation of the alcohol, followed by the...

  • Which of the following compounds are potentia acetic ester synthesis? ne rollowing compounds are "potential' targets...

    Which of the following compounds are potentia acetic ester synthesis? ne rollowing compounds are "potential' targets for either the malonic ester or the aceto hem. For each of these, draw the structurels) of the alkylating agents and indicate if the compound could be made efficiently by this method. Select the best reagent system to prepare each of the following. Use a given method only once LO 00+ АО Hydrolysis of a nitrile made from a five-carbon alcohol Oxidative cleavage of...

  • What results when a secondary alcohol is oxidized? a. a ketone d. an acid b. an...

    What results when a secondary alcohol is oxidized? a. a ketone d. an acid b. an amine e. no reaction c. an aldehyde Which of the following combinations will react spontaneously? A. 12 + Cu2+ B. Pb2+ + Ag C. Zn2+ + Mg D. Sn2+ + Ni2+ The general formula for a cycloalkane can be represented by which of the following? a. C,H, C. CH b. C.H2n+2 d. C.H21-2 In a certain reaction AH =-136 kJ and E, = 96...

  • Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23,...

    Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23, 4.24, 4.26 pg 170 - 4.29, 4.31, pg 171-4.36 pg 175 - 4.59 pg 176- 4.74, 4.75, 4.80 pg 177-4.81, 4.82 pg 188- 5.1, 5.4, 5.5, 5.6, 5.11 - Using Table 5.1 pg 198-5.22, 5.25 pg 203 - 5.29 pg 206 - 5.37 pg 209 - 5.39 pg 2.14 5.61 pg 235-6.11, 6.14, 6.16 156 CHAPTER 4 Introduction to Organic Compounds...

  • 26) Name the following compound. CH3 H2C=CH-CH2CHCH: A) 1,1-dimethyl-3-butane B) 4-methyl-1-pentene C) hexene D) 2-methyl-4-pentene E)...

    26) Name the following compound. CH3 H2C=CH-CH2CHCH: A) 1,1-dimethyl-3-butane B) 4-methyl-1-pentene C) hexene D) 2-methyl-4-pentene E) 2-methylpentene 27) Name the following compound. CI A) 2,3,5-trichlorobenzene B) trichlorostyrene C) 1,3,4-trichlorobenzene D) 1,3,4-trichlorohexene E) 1,2,4-trichlorobenzene 28) Identify the formula for an alkene. A) CnH2n+4 B) CnH2n+2 C) CnH2n D) CnH2n-4 E) CnH2n-2 29) Name the following compound. A) 1,4-bromocyclohexene B) 1,4-dibromobenzene C) 3,6-dibromobenzene D) 2,5-dibromobenzene E) 2,5-dibromocyclohexene 30) Name the following compound. CECH CH,CH,CHCH A) 2-ethynebutane B) 3-methyl-1-pentyne C) 3-methyl-4-pentyne D) 3-ethyl-1-butyne...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT