given
ΔV = 24600 volts
q = 1.6 x 10-19 C
m = 9.1 x 10-31 kg
using conservation of energy
1/2 m vi2 + PEi = 1/2 m vf2 + PEf
0 + PEi = 1/2 m vf2 + PEf
1/2 m vf2 = PEf - PEi
1/2 m vf2 = ΔPE
ΔPE = q ΔV
1/2 m vf2 = q ΔV
vf2 = 2 q ΔV / m
= 2 x 1.6 x 10-19 x 24600 / 9.1 x 10-31
vf2 = 8.65054 x 1015
vf = 0.93008279 x 108 m/sec
In a television picture tube, electrons strike the screen after being accelerated from rest through a...
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