Question

In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 24 600 V. The speeds of the electrons are quite large, and for acourate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. Select Tutal
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Answer #1

given

ΔV = 24600 volts

q = 1.6 x 10-19 C

m = 9.1 x 10-31 kg

using conservation of energy

1/2 m vi2 + PEi = 1/2 m vf2 + PEf   

0 + PEi = 1/2 m vf2 + PEf   

1/2 m vf2 = PEf - PEi

1/2 m vf2 = ΔPE

ΔPE = q ΔV

1/2 m vf2 = q ΔV

vf2 = 2 q ΔV / m

= 2 x 1.6 x 10-19 x 24600 / 9.1 x 10-31

vf2 = 8.65054 x 1015

vf = 0.93008279 x 108 m/sec

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