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A student adds 50.0 mL of H2O to 25.0 mL of 0.881 M Ca(OH)2. a) what...

A student adds 50.0 mL of H2O to 25.0 mL of 0.881 M Ca(OH)2.

a) what is the concentration of Ca 2+ in the diluted solution?

b) What is the concentration of hydroxide ion in the diluted solution?

So far I have solved for the concentration of H2O

M1V1 = M2V2 --> M(50.0) = 25.0(.881) M1= 0.441 M H2O

I just do not know where to go from there.

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Answer #1

ICQ COH)2) = 0.881H, 2sme ncacol = (0.881 x 25) => ncaloh) = 22.025 mmol Now some of H₂O is calced total volume = 25+ 50 = 15

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