Hi!
Our first step for this problem is to convert 10.0 grams of FeCl3 to moles using its molar mass (162.2 grams per mole):
Next, we calculate the molarity by dividing the 0.062 moles of FeCl3 by the volume in Liters (275 mL = 0.275 Liters). This is our final answer:
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What is the molarity of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3...
What is the molarity (M) of FeCl3 in a solution prepared by dissolving 10.0 g of FeCla in enough water to make 275 mL of solution? O A) 2.24 x 104 O B) 3.82 x 10-2 O c) 0.224 O D) 0.382 O E) 4.46 OF) 3.82 x 102 O G) 4.46 x 103
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