On a hot day, you take a six-pack of soda on a picnic, cooling it with ice. Each empty (aluminum) can weighs 12.5 g. A can contains 12.0 oz of soda. The specific heat of aluminum is 0.902 J/g · °C; take that of soda to be 4.10 J/g · °C.
(a) How much heat must be absorbed from the six-pack to lower the temperature from 25.0° to 5.0°C?
(b) How much ice must be melted to absorb this amount of heat? (ΔHfus of ice is given in Table 8.2.)
Reference Table 8.2:
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