The formaldehyde content of a pesticide preparation was determined by
weighing 0.2985 g of the liquid sample into a flask containing 50.0 mL of 0.0959 M NaOH and 50 mL of
3% H2O2. Upon heating, the following reaction took place:
OH2 + HCHO + H2O2 → HCOO2 + 2H2O
After cooling, the excess base was titrated with 22.71 mL of 0.053700 M H2SO4. Calculate the percentage
of HCHO (30.026 g/mol) in the sample.
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