Aluminum and chlorine combine to form aluminum chloride. (9.1, 9.2, 9.3, 9.4)
2Al(s) + 3Cl2(g) → 2AlCl3(s)
a. How many moles of Cl2 are needed to react with 4.50 mol of Al?
b. How many grams of AlCl3 are produced when 50.2 g of Al reacts?
c. When 13.5 g of Al reacts with 8.00 g of Cl2, how many grams of AlCl3 can form?
d. If 45.0 g of Al and 62.0 g of Cl2 are mixed, and 66.5 g of AlCl3 is actually obtained, what is the percent yield of AlCl3 for the reaction?
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