When ammonia (NH3) reacts with fluorine (F2), the products are dinitrogen tetrafluoride and hydrogen fluoride.
2NH3(g) + 5F2(g) → N2F4(g) + 6HF(g)
a. How many moles of each reactant are needed to produce 4.00 mol of HF?
b. How many grams of F2 are required to react with 25.5 g of NH3?
c. How many grams of N2F4 can be produced when 3.40 g of NH3 reacts?
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