Assign absolute configurations as R or S to each of the following compounds:
(a)
(b)
(c)
(d)
Sample Solution (a) The highest ranking substituent at the chirality center of 2-methyl-1-butanol is CH2OH; the lowest is H. Of the remaining two, ethyl outranks methyl.
Order of precedence: CH2OH > CH3CH2 > CH3 > H
The lowest ranking group (hydrogen) points away from us in the drawing. The three highest ranking groups trace a clockwise path from CH2OH → CH3CH2 → CH3.
This compound therefore has the R configuration. It is (R)-(+)-2-methyl-1-butanol.
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