(This exercise is for people who have taken some calculus.) The Prime Number Theorem says that the counting function for primes, π(x), is approximately equal to x/ ln(x) when x is large. It turns out that π(x) is even closer to the value of the definite integral
(a) Show that
This means that and x/ ln(x) are approximately the same when x is large. [Hint. Use L’Hˆopital’s rule and the Second Fundamental Theorem of Calculus.]
(b) It can be shown that
Use this series to compute numerically the value of for x = 10, 100, 1000, 104, 106, and 109. Compare the values you get with the values of π(x) and x/ ln(x) given in the table on page 92. Which is closer to π(x), the integral or the function x/ ln(x)? (This problem can be done with a simple calculator, but you’ll probably prefer to use a computer or programmable calculator.)
(c) Differentiate the series in (b) and show that the derivative is actually equal to 1/ ln(t). [Hint. Use the series for ex.]
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.