The reaction of [RuCl2(PPh3)(dppb)l with phen leads to the loss of PPh3 and the formation of an octahedral complex, X.
The solution 31P{1H} NMR spectrum of a freshly made sample of X shows a singlet at 8 33.2 ppm. The sample is left standing in the light for a few H3C hours, after which time the 31P{ ‘HJ NMR spectrum is again recorded. The signal al 8 33.2 ppm has diminished in intensity, and two doublets at 8 44.7 and 32.4 ppm (relative integrals 1:1, each signal with J / = 31 Hz) have appeared. Rationalize these data.
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