Find a value z0 of the standard normal random variable z such that
a. P(z ≤ z0) = .0401
b.P(-z0 ≤ z ≤ z0) = .95
c. P(-z0≤ z ≤ z0) = .90
d.P(-z0≤ z ≤ z0) = .8740
e.P(-z0≤ z ≤ 0) = .2967
f. P(-2 6 z 6 z0) = .9710
g. P(z ≥ z0) = .5
h. P(z ≥ z0) = .0057
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