Problem

The width of a slot of a duralumin forging is (in inches) normally distributed with μ =...

The width of a slot of a duralumin forging is (in inches) normally distributed with μ = .9000 and σ = .0030. The specification limits were given as .9000 ± .0050.

(a) What percentage of forgings will be defective?

(b) What is the maximum allowable value of σ that will permit no more than 1 in 100 defectives when the widths are normally distributed with μ = .9000 and σ?

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