•• In Example 13.1 [Eq. (13.2)] we estimated the potential energy (PE) of any one ion in solid NaCl. (a) Make a corresponding estimate of the PE of any one ion in KCl whose crystal structure is the same as NaCl, but whose nearest-neighbor separation is 0.31 nm. (b) This estimate ignores the repulsive forces that come into play when the ions get very close. Thus, your answer should be somewhat below the observed value of −7.2 eV. Use this observed value to find the atomic cohesive energy of KCl in eV/atom. (The ionization energy of K is 4.3 eV; the electron affinity of Cl is 3.6 eV.)
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