Problem

The nuclide 226 88Ra decays to gaseous 222 86Rn with a t1/2 = 1600 y. The nuclide 222 86...

The nuclide 226 88Ra decays to gaseous 222 86Rn with a t1/2 = 1600 y. The nuclide 222 86Rn in turn α decays with a shorter lifetime, t1/2 = 3.82 days. If radium is originally placed in an evacuated closed container, the amount of radon gas builds up and can be measured. It is found that radon gas builds up to a constant value and that as much 222Rn is being produced as decays. This process is called secular equilibrium, and the activities are equal. (a) Show that radon builds up at the rate dN2/dt = λ1N1 - λ2N2 where λ1, N1 and - λ2, N2 are the decay constants and number of nuclei present for radium and radon, respectively. (b) Because the decay of 226Ra is so slow, assume that N1 is constant and show that

(c) Show that after a long time, secular equilibrium is reached.

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