Consider the following reversible isothermal two-step process: vaporization of one mole of liquid i at Pnbp,i and 1 atm to gaseous i with molar volume Vm,i; volume change of gas i from Vm,i to a certain fixed molar volume Show that if ΔSm for the two-step process is assumed to be the same for any liquid, one obtains the Trouton‒Hildebrand‒Everett rule ΔvapSm,nbp = a + R In (Tnbp/K), where a is a constant.
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