Problem

3.a.CBAY000000110101011 11001101 11101111 1b.CBAY000100110101011 11001101 11101111 0c.CBAY...

3.

a.

CBAY
0000
0011
0101
011 1
1001
101 1
1101
111 1

b.

CBAY
0001
0011
0101
011 1
1001
101 1
1101
111 0

c.

CBAY
0000
0011
0101
011 0
1001
101 0
1100
111 1

d.

BAY
001
010
100
110

e.

BAY
001
010
100
111

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