Radical chlorination of CH3CH3 forms two minor products X and Y of molecular formula C2H4Cl2.
a. Identify the structures of X and Y from the following 1H NMR data:Compound X: singlet at 3.7 ppm Compound Y: doublet at 2,1 and quartet at 5.9 ppm
b. Draw a stepwise mechanism that shows how each product is formed from CH3CH3.
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