The specific rotatory power for sucrose dissolved in water at 20°C (λo = 589.3 nm) is +66....

The specific rotatory power for sucrose dissolved in water at 20°C (λo = 589.3 nm) is +66.45° per 10 cm of path traversed through a solution containing 1 g of active substance (sugar) per em of solution. A vertical -state (sodium light) enters at one end of a 1-in tube containing 1000 cm3 of solution, of which 10 g is sucrose. At what orientation will the -state emerge?