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Two forces act on the hook. Determine the magnitude of the resultant force.

Two forces act on the hook. Determine the magnitude of the resultant force. 

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Net Force in X-direction = 200cos30 + 500cos70 = 200*.866+500*.342 = 344.2N

Net Force in Y-direction = 200sin30 + 500sin70 = 200*.5+500*94 = 570 N

The net-force is sqrt(344.2^2 + 570^2) = 665.86 in the direction of tan-1(Fy/Fx)
= tan-1(570/344.2)
= tan-1(1.656)
= 58.87

So, in the direction of 58.87 degrees clockwise from the x axis , the resultant force of 665.86 N is appied

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