Question

How many different letter arrangements can be formed from the letters PEPPER?

Why the answer is not 6!? Don't just solve the question, if you do so , it goes to trash thank you. So explain why is not 6! and follow the comment

Answer 1

In the word PEPPER,

Number of P = 3

Number of E = 2

Number of R = 1

Number of different letter arrangements can be formed from the letters PEPPER

$= \frac{6!}{3!*2!*1!}$

$= \frac{6!}{3!*2!}$

$= \frac{6*5*4}{2!}$

$= 6*5*2$

$= 60$

since three P's can be in 3! ways among themselves but they just look the same, so we have to ignore all of those cases where three P's are together and in 3! permutations among themselves, same thing happens with E's