Solution:
Given
n = 195 sample size
X = 162
. Sample proportion
level of significance.
The 95% confidence interval for population proportion p is
At
. From Z table
( 0.777280, 0.8827199)
( 0.7773, 0.8827)
The 95% confidence interval for population proportion p is
( 0.7773, 0.8827)
Use the given degree of confidence and sample data to construct a confidence interval for the...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. nequals=195, xequals=162; 95% confidence A. 0.777less than<pless than<0.884 B. 0.789less than<pless than<0.873 C. 0.788less than<pless than<0.873 D. 0.778less than<pless than<0.883
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. nequals=195, xequals=162; 95% confidence A. 0.788less than<pless than<0.873 B. 0.777less than<pless than<0.884 C. 0.789less than<pless than<0.873 D. 0.778less than<pless than<0.883
1.23 25) 25) Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. * = 195, x = 162: 95% confidence A) 0.777 < p < 0.884 B) 0.789 < p < 0.873 C) 0.778 <p < 0.883 D) 0.788 <p <0.873
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n = 62, x = 25; 95% confidence OA) 0.580 < p < 0.596 B) 0.280 < p < 0.526 OC) 0.300 < p < 0.506 OD) 0.281 < p < 0.525 E) 1.280 < p < 2.526 F) 0.301 < p < 0.505
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places of 107 randomly selected adults, 34 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure O A. 22.953% <p < 40.598% OB. 21.288% <p<42.263% OC. 20.163% <p < 43.389% D. 24.349% <p <39.203%
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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 24) Of 80 adults selected randomly from one town, 64 have health insurance. Find a 90% confidence 24) interval for the true proportion of all adults in the town who have health insurance. A) 0.696 < p0.904 C) 0.712 <p0.888 B) 0.685 <p<0.915 D) 0.726< p<0.874 25) Of 382 randomly selected medical students, 27 said that they planned to work in...
Use the given degree of confidence and sample data to construct a confidence interval for the population mean µ. Assume that the population has a normal distribution. please show ur work, thanks Use the given degree of confidence and sample data to construct a confidence interval for the population mean . Assume that the population has a normal distribution. You need to show work. 5) 5) n = 12, x = 25.3, s = 4.5, 99 percent A) 21.28 <...
1. Use the given degree of confidence and sample data to construct a confidence interval for the point) population proportion p. A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval. 0 0.438<p0.505 0 0.444 p0.500 0 0.435<p<0.508 O 0.471 p0.472 2. Use the given data to find the minimum sample size required...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places. Of 89 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.