x (Number of TV’s) |
P(x) |
xP(x) |
x2 |
x2P(x) |
1 |
0.32 |
|||
2 |
0.51 |
|||
3 |
0.12 |
|||
4 |
0.05 |
x | P(x) | xP(x) | x2 | x2P(x) |
1 | 0.32 | 0.32 | 1 | 0.32 |
2 | 0.51 | 1.02 | 4 | 2.04 |
3 | 0.12 | 0.36 | 9 | 1.08 |
4 | 0.05 | 0.20 | 16 | 0.80 |
1.90 | 4.24 |
(a) Probability that a household owns more than 2 televisions = P(X > 2) = 0.12 + 0.05 = 0.17
(b) Probability that a household owns at most 2 telivisions = P(X ≤ 2) = 0.83
(c) Mean = = 1.90
Variance = = 0.63
Standard deviation = √0.63 = 0.794
(d) Since the mean in 1.90, we would send 2 program diaries to each household in the survey
(e) No, this is not a believable claim since it is even high than the maximum number of televisions in a household which is 4
A study conducted by a TV station showed the number of televisions per household and the...
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