Question

A stone thrown downward with an initial velocity of 34.3 m/sec travel a distance of s meters, where: s(t)=4.9t + 34.3t and t is in seconds

A stone thrown downward with an initial velocity of 34.3 m/sec travel a distance of s meters, where:
s(t)=4.9t + 34.3t
and t is in seconds. If a stone is thrown downward at 34.3m/sec from a height of 294 m, how long will it take the stone to reach the ground?
I am putting 294 in for t and trying to solve it that way. Is this correct? If not please let know where I am going wrong.

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Answer #1
the 4.9t should be 4.9t^2 ... the 294 is the s value, NOT the t value 294=4.9t^2+34.3t
answered by: Chris Dane
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A stone thrown downward with an initial velocity of 34.3 m/sec travel a distance of s meters, where: s(t)=4.9t + 34.3t and t is in seconds
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