Two stones are separated by a vertical distance y (in meters) from each other. One stone is thrown down with an initial velocity v01=23 m/s
Two stones are separated by a vertical distance y (in meters) from each other. One stone is thrown down with an initial velocity v01=23 m/s and the other is thrown up from the ground with an initial v02 = 14 m/s at the same time the other is thrown
Part (a) How far, in meters, must they be separated so they hit the ground at the same time?
Part (b) what is the impact velocity, in meters per second, of the first stone?
Part (c) What is the impact velocity, sn meters per second, of the second stone?
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Two stones are separated by a vertical distance y (in meters) from each other. One stone is thrown down with an initial velocity v01=23 m/s
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