Balance the following Redox Equations in Basic Mediums.
Redox Reactions in Basic Solution
1. Al(s) + MnO4¯ (aq) ¾® MnO2(s) + Al(OH)4¯ (aq)
2. NO2¯ (aq) + Al(s) ¾® NH3(aq) + AlO2¯ (aq)
3. Cr(s) + CrO42-(aq) ¾® Cr(OH)3(s)
Note: Cr(OH)3 is found in BOTH half reactions!
4. Cl2(aq) + Br2(l) ¾® OBr¯ (aq) + Cl¯ (aq)
5. S8(aq) + MnO4¯ (aq) ¾® SO42-(aq) + MnO2(s)
1. Al(s) + MnO4-(aq) + 2H2O = MnO2(s) + Al(OH)4- (aq)
2. NO2-(aq) + 2Al(s) + OH- + H2O = NH3(aq) + 2AlO2-(aq)
3. Cr(s) + CrO42-(aq) + 4H2O = 2Cr(OH)3(s) + 2OH-
4. Cl2(aq) + Br2(aq) +4OH- = 2OBr-(aq) + 2Cl-(aq) + 2H2O
5. S8(aq) + 16MnO4-(aq) = 8SO42-(aq) + 16MnO2
Balance the following Redox Equations in Basic Mediums. Redox Reactions in Basic Solution 1. Al(s) + ...
Balance the redox reactions: basic: ClO-(aq)+Cr(OH)4-(aq)----> CrO42-(aq)+Cl-(aq) MnO4-(aq)+Br-(aq)--> MnO2(s)+BrO3-(aq) NO2-(aq)+Al(s)--->NH3(g)+AlO2- Aidic: ClO4-(aq)+Cr(OH)4---->ClO3-(aq)+Cl2(g)
Problem 2. Complete and balance the following equations for the reactions occurring in basic solution: a. MnO4-(aq)+C2O42-(aq)→MnO2(s)+CO2(g) b. NO2-(aq) + Al(s) → NH3(g) + Al(OH)4-(aq) Answer: a. 4H2O + 2MnO4- + 3C2O42- → 2MnO2 + 8OH- + 6CO2 b. 5H2O + NO2- + OH- + 2Al → NH3+ 2Al(OH)4-
How do I solve the following redox reactions? What are the balanced half-reactions? What is the final balanced equation? Problems 1. MnO4 (aq) + SO32- (aq) → MnO2 (s) + SO42- (aq) in basic solution 2. NO2" (aq) + Al(s) NH3(aq) + Al(OH)4 (aq) in basic solution 3. Mn2+ (aq) + NaBiO3 (s) → Bi* (aq) + MnO4 (aq) + Nat (aq) in acidic solution 4. As2O3 (s) + NO3- (aq) → H3ASO4 (aq) + N2O3 (aq) in acidic solution...
Balance Redox Equations (Basic Solution) with steps. 1. Mn^2+ (aq) + Br2(l) = MnO2 (s) + Br^- (aq) 2. NO2^- (aq) + MnO4^- (aq) = NO3^- (aq) + MnO2 (s) 3. N2H4 (g) + ClO3^- (aq) = NO(g) + Cl^- (aq)
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO2 (s) + Cl → Mn2+ + Cl2 (g) (b) (acid solution): NaBiO; (s) + Ce3+ BiO+ + Ce4+ + Na+ (c) (basic solution): Fe(OH)2 (s) + CrO42- → Fe,0, (s) + Cr(OH)4
Balance the following redox reaction in basic solution. You will need to show all work including half-reactions, balancing of O, H, electrons, and the final balanced reaction. Cr(OH)3(s) + ClO3−(aq) ® CrO42−(aq) + Cl−(aq) please show work
[15] Balance the following redox reactions: {3 points each} a) Cr2O72-(aq) + Cl-(aq) → Cr3+(aq) + Cl2(g) (acidic medium) b) Al(s) + MnO4-(aq) → MnO2(s) + Al(OH)4-(aq) (basic medium)
Balance the following redox reactions that occur in basic solution A) Zn (s) + MnO4-1 (aq) -> Zn(OH)4-2 (aq) + MnO2 (s) B) NO3-1 (aq) + Si (s) -> NH3 (aq) + SiO3-2 (aq)
Balance the following redox reactions: a) CN− + MnO4− → CNO− + MnO2 (basic solution) b) O2 + As → HAsO2 + H2O (acidic solution) c) Br− + MnO4− → MnO2 + BrO3− (basic solution) d) NO2 → NO3− + NO (acidic solution) e) ClO4− + Cl− → ClO− + Cl2 (acidic solution) f) AlH4− + H2CO → Al3+ + CH3OH (basic solution)
Balance the following redox reaction in basic solution. You will need to show all work including half-reactions, balancing of O, H, electrons and the final balanced reaction. Cr(OH)3(s) + ClO3−(aq) --- CrO42−(aq) + Cl−(aq)