For the gas propane (C3H8), (a) how many grams are in 1.50 moles of C3H8, (b) how many moles are in 25.0 grams of C3H8, (c) how many molecules of C3H8 are in 25.0 moles of C3H8 and finally (d) what is the percent carbon in C3H8?
a)
Molar mass of C3H8,
MM = 3*MM(C) + 8*MM(H)
= 3*12.01 + 8*1.008
= 44.094 g/mol
use:
mass of C3H8,
m = number of mol * molar mass
= 1.5 mol * 44.09 g/mol
= 66.14 g
Answer: 66.1 g
b)
Molar mass of C3H8,
MM = 3*MM(C) + 8*MM(H)
= 3*12.01 + 8*1.008
= 44.094 g/mol
mass(C3H8)= 25.0 g
use:
number of mol of C3H8,
n = mass of C3H8/molar mass of C3H8
=(25 g)/(44.09 g/mol)
= 0.567 mol
Answer: 0.567 mol
c)
use:
number of molecules = number of mol * Avogadro’s number
number of molecules = 25 * 6.022*10^23 molecules
number of molecules = 1.506*10^25 molecules
Answer: 1.51*10^25 molecules
d)
Molar mass of C3H8,
MM = 3*MM(C) + 8*MM(H)
= 3*12.01 + 8*1.008
= 44.094 g/mol
MM of C3H8 = 44.094 g/mol
Lets calculate the mass of element
mass of C = 3*MM(C)
= 36.03 g
Mass % of C = (36.03*100)/44.094
= 81.7118 %
Answer: 81.7 %
For the gas propane (C3H8), (a) how many grams are in 1.50 moles of C3H8, (b)...
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