Question

Assume that the partial pressure of sulfur dioxide

Assume that the partial pressure of sulfur dioxide, PSO2 , is equal to the partial pressure of dihydrogen sulfide, PH2S , and therefore PSO2=PH2S. If the vaporpressure of water is 27 torr, calculate the equilibrium partial pressure of SO2 (PSO2) in the system at 298 K. Express the pressure in atmospheres to two significantfigures.
PSO2= __ atm
In part A, Kp= 8*10^15
:( I keep getting it wrong.
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Answer #1
convert the given pressure of water to atm, which is: .036
Kp is 8.0*10^15

Kp=P(H2O)^2/P(SO2)P(H2S)^2

8.0*10^15 = (0.036)^2/x^3

(8.0*10^15).(x^3)=1296*10^-6

take the cube root of both sides
(2.0*10^5).x=10.903*10^-2
x=P(SO2)=5.45*10^-7
answered by: Alok
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