mastering chemistry
Homework Answers
Kp = p[I]^2 / p[I2]
= (0.32 atm)^2 / 0.41 atm
= 0.250
When volume is halved, the system moves towards the side with less number of moles i.e. reactants side. When volume is halved, pressure is doubled:
I2 <------> 2 I
0.82 0.64
+x -2x
(0.82+x) (0.64-2x)
Kp = 0.250 = (0.64-2x)^2 / (0.82+x)
Solving, we get x = 0.0825
So p[I2] = 0.82 + 0.0825 = 0.9025 atm
p[I] = 0.62 - 2(0.0825) = 0.455 atm
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